WebNov 1, 2016 · Explanation: Positive divisors of 120 are factors of 120. In number 120, sum of digits is 3, a multiple of 3, hence it is divisible by 3. As last digit is 0, it is also divisible by 2 and 5 (and also 10. The last two digits being 20, it is also divisible by 4. Hence, some factors are 2, 3, 4 and 5. WebWe know that N=1 has just 1 divisor: Let maxDivisors = 1 // number of divisors of 1 Let numWithMax = 1 for each integer N from 2 to 10000: Count the number of divisors of N If that number is greater than maxDivisors: Let maxDivisors = the number of divisors of N Let numWithMax = N Output maxDivisors and numWithMax
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WebJan 25, 2015 · It has 1, 2, 3, 4, 6, 12 as its divisors; so, total number of divisors of 12 is 6. Now the method I learned: x = p 1 a p 2 b, where p 1 and p 2 are prime numbers. Now, x … WebSum of all the Divisors of 150, including itself 372 Sum of the Proper Divisors of 150 222 Properties of the number 150 The integer 150 is an even number. The integer 150 is a … theotetos
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WebNov 1, 2016 · Similarly, it is also divisible by 10 (as 2 and 5 are coprime), 12 (as 3 and 4 are coprime),and 15 too (as 3 and 5 are coprime). As dividing by 4 we get, 30 which is even, 8 … WebMar 22, 2014 · Once you factorize a number as N = p 1 a 1 p 2 a 2 p 3 a 3... p n a n, p i prime for every i, a i > 0 for every i the number of divisors is given by ( a 1 + 1) ( a 2 + 1) ( a 3 + 1)... ( a n + 1). WebOct 19, 2024 · How many positive divisors does the integer n have? Here is what I have: p 1 n 1 has the following divisors: 1, p 1, p 1 2, p 1 3,... p 1 n 1 So that is ( n 1 + 1) divisors And for p 2 n 2 it would be ( n 2 + 1), and so on. So n has ( n 1 + 1) ( n 2 + 1) ( n 3 + 1)... ( n j + 1) divisors. Is this correct? discrete-mathematics solution-verification shubie courthouse