How many kilojoules are required at 0 to melt
Web29 feb. 2016 · It takes 4.2 joules per gram of water to raise the temperature by one degree Celsius. The total number of joules is then 190.176 kilojoules. Web19 apr. 2024 · 2 answers heat ice to 0ºC ... 10.0 g *10.0 ºC * 2.09 J/gºC melt ice ... 10.0 g * 334 J/g heat water to 100ºC ... 10.0 g * 4.184 J/gºC * 100.0 ºC boil water ... 10.0 g * 2.23 kJ/g heat steam to 115ºC ... 10.0 g * 1.84 J/gºC * 15.0 ºC add the steps answered by scott April 19, 2024 2.83 kJ answered by maybe May 9, 2024 Answer this Question
How many kilojoules are required at 0 to melt
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WebThe energy required to melt 1.00 g of ice at 0 degrees Celsius is 333 J. If one ice cube has a mass of 62.0 g and a tray contains 16 ice cubes, what quantity of energy is required to... Web8 kilojoules are required. Kj = 25 g. 25 g x 334 J = 8350 J x 1 KJ = 8 = 8 KJ. g 1000 Q5 How many kilojoules are required to melt 15 g of ice at 0°C, and raise the temperature of the liquid that forms to 85°C? 5 kilojoules are required to melt the 15 g of ice and 10 kilojoules are required to raise the temperature. 15 g x 334 = 5010 = 5 = 5 ...
Web30 sep. 2024 · Answer:- 8.35 kJ Solution:- It asks to calculate the heat required to melt 25 g of ice at 0 degree C. It is a phase change and the heat energy is calculated by using the formula: where q is the heat energy, m is the mass and is the enthalpy of fusion of ice. … Web30 sep. 2024 · This means for every mole of melting ice, we must apply 6.02 kJ of heat. We can calculate the heat needed with the following equation: = Δ. where: q = heat. n = moles (0.71 mole = 12.8 g water) ΔH = enthalpy (for water at 0 temperature is 6.02) This problem can be broken into three steps: 1.
Web2 apr. 2024 · And hence finally we have, ⇒ Δ Q t o t a l = 4520.7 J. Therefore, energy needed to melt 15 grams of ice to water at 0 ∘ C is 4520.7J. Note: Make sure to convert the mass given in grams into kilograms as the specific heat and the latent heat is given in terms of J/kg. 1 grams is equal to 1 1000 k g. Web21 mrt. 2024 · Answer; 3.4 kJ Explanation; Taking the mass of water as 10.0 g Moles of water = Mass /molar mass Moles of water in 10.0 g; = 10g H2O x 1mol/18g =0.56mol But, 1 mole of water = 6.01 kJ Hence; 6.01kJ/1mol H2O= x kJ/.56mol, x = 3.4kJ Advertisement Use the picture below to answer the question. Comparing the two waves, wave B has a...
Web12 sep. 2011 · What are the Kilojoules needed to melt 24.0g of ice at O degrees C, warm the liquid to 100 degree C and change it to steam at 100 degree C? Thank you, asked by Sue September 12, 2011 1 answer add the heats. melt ice: mass*heatfusionice water : mass*spcificheatwater (100-0) make steam: mass*heatvaporization bobpursley …
WebHow many joules of energy are required to make 100 grams of ice at 0 ΟC completely melt? Ernest Z. Converting 100. g of ice at 0.00 °C to water vapour at 100.00 °C requires … canaways toursWebScience Chemistry Melting lead requires 5.25 cal/g. Calculate how many kilojoules are required to melt 1 lb of lead. Melting lead requires 5.25 cal/g. Calculate how many kilojoules are required to melt 1 lb of lead. Question Melting lead requires 5.25 cal/g. Calculate how many kilojoules are required to melt 1 lb of lead. Expert Solution can a wav file have a virusWebFor example, many weekday newspaper puzzles (such as the American New York Times crossword puzzle) are 15×15 squares, while weekend puzzles may be 21×21, 23×23, or 25×25. The New York Times puzzles … fishing4everWeb9 nov. 2024 · To get heat in Joules:q = (25 g)x(334 J/g)q = 8350 JIt's just as easy to express the heat in terms of calories:q = m·ΔHfq = (25 g)x(80 cal/g)q = 2000 calAnswer: The … can a way out be played cross platformWeb6 nov. 2024 · 2 answers 8350 joules answered by ghoulian hooligan November 6, 2024 heat fusion is 6.01 kJ/mol. mols = 25/18 = about 1.38 Then 1.38 x 6.01 = ? kJ. That answer above is VERY close. DrBob222 November 6, 2024 Answer this Question Still need help? You can or browse more science questions. fishing 4castWeb5 apr. 2024 · Calculate how much energy is required to heat 500 g of ice at -20 °C to liquid water at 60 °C. (Heat capacity of water and ice are 4.18 J/(K · g) and 2.09 J/(K · g), … fishing4complimentsWebThe calorie is a unit of energy that originated from the obsolete caloric theory of heat. For historical reasons, two main definitions of "calorie" are in wide use. The large calorie, … fishing 4cast florida sportsman